WOBBLCH3COOH(aq) + NaHCO3(s) -> CH3COONa(aq) + H2O(l) + CO2(g)

how much gas does it make and does it get warm or cold?

Report
2026-10-15 18:52
OK

CH3COOH(aq) + NaHCO3(s) -> CH3COONa(aq) + H2O(l) + CO2(g) takes in 31.1 kJ per mole as written and goes forward on its own at 298 K (dG = -13.3 kJ, K = 214). At equilibrium 99.5% of it reacts at 1.01 bar. In 1201 g of vinegar at 5% it cools the solution by 6.2 K. It gives off 24.5 L of gas per mole at 298 K and 101 kPa.

reaction enthalpy
31.1 kJ
Gibbs energy
-13.3 kJ
equilibrium constant
K = 214
temperature change
-6.2 K

Confidence high

  • passed element and charge balance, data, equilibrium

Simulation

Reaction Gibbs energy against temperature, below zero it goes forward
Reaction Gibbs energy against temperature, below zero it goes forward

Checks

statuscheckresult
passelement and charge balanceC, H, Na, O and charge balance exactly
passdataevery species comes from NASA Glenn thermodynamic data and NBS tables
passequilibriumat equilibrium 99.5% of the reactants have reacted, where the reaction quotient matches K = 10^2.33 to 1e-14 in its logarithm

Assumptions

  1. Wobbl guessed: temperature not given: assumed 25 C (298.15 K).
  2. Wobbl guessed: pressure not given: assumed 1 atm.
  3. The products come from an acid on a carbonate.
  4. Standard states, 1 bar for gases and 1 mol/kg for species in water, with data from NASA Glenn thermodynamic data (JANAF and ATcT based) and NBS tables (Wagman et al. 1982).
  5. Species in water are ideal, with activity equal to molality, which holds for dilute solutions.
  6. Thermodynamics says how far and with how much heat a reaction goes, not how fast. A reaction that can go may still need a spark, a catalyst or time.