WOBBLactuator.step
does the plunger pull 5 N at 0.8 A?
OK
The field pushes 'actuator 3' with 6.22 N, mostly along -0.00158, 0.00127, -1 (-0.00984, 0.00787, -6.22 N), with 0.353 mN m of torque about its center. That is enough for the 5 N needed. 'actuator 2' has 96 mH.
force
6.22 N
torque
0.353 mN m
inductance
96 mH
mesh
33,388 nodes
Confidence high
- passed mesh convergence, action and reaction, virtual work, energy balance, amp turns, nonlinear solve
Simulation
Checks
| status | check | result |
|---|---|---|
| pass | mesh convergence | the force on 'actuator 3' moved from 6.04 to 6.22 N on the finer mesh (2.9%) |
| pass | action and reaction | the forces on all 3 bodies add up to 0.0116 N, 0.19% of the largest, where they should cancel |
| pass | virtual work | Maxwell stress gives 6.04 N on 'actuator 3' along its pull, and moving it 0.076 mm each way changes the co-energy by 6.05 N times the move (0.072% apart) |
| pass | energy balance | stored energy plus co-energy is 61.4 mJ and flux linkage times current is 61.4 mJ (1.3e-10% apart) |
| pass | amp turns | the current through every coil's cross section is N times I to 2.2e-14%, along the winding's own shape |
| pass | nonlinear solve | Newton iterations on the steel's BH curves reached a relative residual of 9.4e-09 in 3 iterations |
| info | saturation of actuator 1 | 'actuator 1' peaks at 1.07 T against its 1.48 T knee |
| info | saturation of actuator 3 | 'actuator 3' peaks at 0.838 T against its 1.48 T knee |
Assumptions
- Magnetostatic: steady currents and fields, no eddy currents.
- The air reaches to infinity, mapped by a spherical shell.
- 'actuator 1' is Low carbon steel 1010, nonlinear BH curve, no hysteresis.
- 'actuator 2' is a coil of 1100 turns at 0.8 A, the current spread evenly over its cross section.
- 'actuator 3' is Low carbon steel 1010, nonlinear BH curve, no hysteresis.
- The winding axis of 'actuator 2' is its hole's axis, +z; current circulates right handed about it (write axis -z to reverse it).